Here is a question testing concepts of Quadratic equation and nature of roots of quadratic equation.
If y = x2 + dx + 9 does not cut the x-axis, then which of the following could be a possible value of d?
I. 0
II. -3
III. 9
A. III only
B. II only
C. I and II only
D. II and III only
E. I and III only
Correct Answer : Choice C. Values that ‘d’ could take are 0 or -3
Explanation
The question states that the curve (parabola) does not cut the x-axis.
If y = x2 + dx + 9 cuts the x-axis then, the points at which it cuts the x-axis will be the roots of the quadratic equation x2 + dx + 9 = 0.
As any point on the x-axis will be a value on the number line, the roots will be real numbers.
However, if the curve does not cut the x-axis, then roots of the quadratic equation will be imaginary.
For a quadratic equation “ax2 + bx + c = 0 to have imaginary roots, the discriminant b2 – 4*a*c < 0 (the discriminant should be negative).
In this equation, d2 – 36 < 0
Or d2 < 36
i.e., -6 < d < 6.
Amongst the values given, d = 0 and d = -3 lie in this range.
Hence, choice C.
Amit in Pensieve.. says
Hi Sir
Can u please clarify -6<d<6 after
d^2 < 36 ?
the concept i need to understand here inequality operator change.